Codeforces Round #319 (Div. 2)A Multiplication Table

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2023-06-09 18:24:55 197浏览

Codeforces Round #319 (Div. 2)A Multiplication Table,思路:水题#includeusingnamespacestd;intmain(){intn,x;cin>>n>>x;inta


思路:水题



#include<bits\stdc++.h>
using namespace std;
int main()
{
	int n,x;
	cin >> n >>x;
	int ans = 0;
	for(int i = 1;i<=n;i++)
	{
        if(x%i==0&&x/i<=n)
			ans++;
	}
	cout <<ans <<endl;
}




A. Multiplication Table



time limit per test



memory limit per test



input



output


n rows and n columns. The cell located at the intersection of i-th row and j-th column contains number i × j. The rows and columns are numbered starting from 1.

x. Your task is to count the number of cells in a table that contain number x.


Input



n and x (1 ≤ n ≤ 105, 1 ≤ x ≤ 109) — the size of the table and the number that we are looking for in the table.


Output



x


Examples



input



10 5



output



2



input



6 12



output



4



input



5 13



output



0


Note



12



Codeforces Round #319 (Div. 2)A Multiplication Table_c++



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